dNTF
)In this vignette, we consider approximating a non-negative tensor as a product of binary or non-negative low-rank matrices (a.k.a., factor matrices).
Test data is available from toyModel
.
You will see that there are four blocks in the data tensor as follows.
To decompose a binary tensor (\(\mathcal{X}\)), non-negative CP decomposition (a.k.a. non-negative tensor factorization; NTF (Cichocki 2007; CICHOCK 2009)) can be applied. NTF appoximates \(\mathcal{X}\) (\(N \times M \times L\)) as the mode-product of a core tensor \(S\) (\(J \times J \times J\)) and factor matrices \(A_1\) (\(J \times N\)), \(A_2\) (\(J \times M\)), and \(A_3\) (\(J \times L\)).
\[ \mathcal{X} \approx \mathcal{S} \times_{1} A_1 \times_{2} A_2 \times_{3} A_3\ \mathrm{s.t.}\ \mathcal{S} \geq 0, A_{k} \geq 0\ (k=1 \ldots 3) \]
Note that _{k} is the mode-\(k\)
product (CICHOCK 2009) and the core tensor
\(S\) has non-negative values only in
the diagonal element. For the details, see NTF
function of
nnTensor
package.
In BTF, a rank parameter \(J\)
(\(\leq \min(N, M)\)) is needed to be
set in advance. Other settings such as the number of iterations
(num.iter
) or factorization algorithm
(algorithm
) are also available. For the details of
arguments of dNTF, see ?dNTF
. After the calculation,
various objects are returned by dNTF
. BTF is achieved by
specifying the binary regularization parameter as a large value like the
below:
set.seed(123456)
out_dNTF <- dNTF(X, Bin_A=c(1e+2, 1e+2, 1e+2), algorithm="KL", rank=4)
str(out_dNTF, 2)
## List of 6
## $ S : num [1:4] 2.24 2.23 2.24 2.24
## $ A :List of 3
## ..$ : num [1:4, 1:30] 9.99e-01 2.22e-16 2.22e-16 1.00 9.99e-01 ...
## ..$ : num [1:4, 1:30] 1.00 2.22e-16 2.22e-16 2.22e-16 1.00 ...
## ..$ : num [1:4, 1:30] 4.47e-01 9.94e-17 9.93e-17 9.93e-17 4.47e-01 ...
## $ RecError : Named num [1:28] 1.00e-09 2.67e+01 2.45e+01 2.36e+01 2.27e+01 ...
## ..- attr(*, "names")= chr [1:28] "offset" "1" "2" "3" ...
## $ TrainRecError: Named num [1:28] 1.00e-09 2.67e+01 2.45e+01 2.36e+01 2.27e+01 ...
## ..- attr(*, "names")= chr [1:28] "offset" "1" "2" "3" ...
## $ TestRecError : Named num [1:28] 1e-09 0e+00 0e+00 0e+00 0e+00 0e+00 0e+00 0e+00 0e+00 0e+00 ...
## ..- attr(*, "names")= chr [1:28] "offset" "1" "2" "3" ...
## $ RelChange : Named num [1:28] 1.00e-09 2.56e-02 8.80e-02 4.16e-02 3.89e-02 ...
## ..- attr(*, "names")= chr [1:28] "offset" "1" "2" "3" ...
The reconstruction error (RecError
) and relative error
(RelChange
, the amount of change from the reconstruction
error in the previous step) can be used to diagnose whether the
calculation is converged or not.
layout(t(1:2))
plot(log10(out_dNTF$RecError[-1]), type="b", main="Reconstruction Error")
plot(log10(out_dNTF$RelChange[-1]), type="b", main="Relative Change")
The product of core tensor \(S\) and
factor matrices \(A_{k}\) shows whether
the original data is well-recovered by dNTF
.
The histograms of \(A_{k}\)s show that all the factor matrices \(A_{k}\) looks binary.
Here, we define this formalization as semi-binary tensor factorization (SBTF). SBTF can capture discrete patterns from non-negative matrices.
To demonstrate SBMF, next we use a non-negative tensor from the
nnTensor
package. You will see that there are four blocks
in the data tensor as follows.
In SBTF, a rank parameter \(J\)
(\(\leq \min(N, M)\)) is needed to be
set in advance. Other settings such as the number of iterations
(num.iter
) or factorization algorithm
(algorithm
) are also available. For the details of
arguments of dNTF, see ?dNTF
. After the calculation,
various objects are returned by dNTF
. SBTF is achieved by
specifying the binary regularization parameter as a large value like the
below:
set.seed(123456)
out_dNTF2 <- dNTF(X2, Bin_A=c(1e+5, 1e+5, 1e-10), algorithm="KL", rank=4)
str(out_dNTF2, 2)
## List of 6
## $ S : num [1:4] 13.1 31.7 112.1 1474.1
## $ A :List of 3
## ..$ : num [1:4, 1:30] 0.00704 0.00175 0.47548 0.00303 0.00653 ...
## ..$ : num [1:4, 1:30] 0.00905 0.00602 0.10119 0.00226 0.0092 ...
## ..$ : num [1:4, 1:30] 0.1385 0.2206 0.0447 0.0048 0.1523 ...
## $ RecError : Named num [1:101] 1.00e-09 2.46e+04 3.90e+03 2.96e+03 6.38e+03 ...
## ..- attr(*, "names")= chr [1:101] "offset" "1" "2" "3" ...
## $ TrainRecError: Named num [1:101] 1.00e-09 2.46e+04 3.90e+03 2.96e+03 6.38e+03 ...
## ..- attr(*, "names")= chr [1:101] "offset" "1" "2" "3" ...
## $ TestRecError : Named num [1:101] 1e-09 0e+00 0e+00 0e+00 0e+00 0e+00 0e+00 0e+00 0e+00 0e+00 ...
## ..- attr(*, "names")= chr [1:101] "offset" "1" "2" "3" ...
## $ RelChange : Named num [1:101] 1.00e-09 8.23e-01 5.30 3.19e-01 5.36e-01 ...
## ..- attr(*, "names")= chr [1:101] "offset" "1" "2" "3" ...
RecError
and RelChange
can be used to
diagnose whether the calculation is converged or not.
layout(t(1:2))
plot(log10(out_dNTF2$RecError[-1]), type="b", main="Reconstruction Error")
plot(log10(out_dNTF2$RelChange[-1]), type="b", main="Relative Change")
The product of core tensor \(S\) and
factor matrices \(A_{k}\) shows whether
the original data is well-recovered by dNTF
.
recX <- recTensor(out_dNTF2$S, out_dNTF2$A)
layout(t(1:2))
plotTensor3D(X2)
plotTensor3D(recX, thr=0)
The histograms of \(A_{k}\)s show that \(A_{k}\) looks binary.
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## Platform: x86_64-pc-linux-gnu (64-bit)
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