dNMF
)In this vignette, we consider approximating a binary or non-negative matrix as a product of two non-negative low-rank matrices (a.k.a., factor matrices).
Test data is available from toyModel
.
## Warning: no DISPLAY variable so Tk is not available
You will see that there are five blocks in the data matrix as follows.
Here, we consider the approximation of a binary data matrix \(X\) (\(N \times M\)) as a matrix product of \(U\) (\(N \times J\)) and \(V\) (\(M \times J\)):
\[ X \approx U V' \ \mathrm{s.t.}\ U,V \in \{0,1\} \]
This is known as binary matrix factorization (BMF). Zhang (2007) et al. developed BMF by adding
binary regularization term to non-negative matrix factorization (NMF
(Lee and Seung 1999; CICHOCK 2009)). For
the details of NMF, see also NMF
function of nnTensor
package.
In BMF, a rank parameter \(J\)
(\(\leq \min(N, M)\)) is needed to be
set in advance. Other settings such as the number of iterations
(num.iter
) or factorization algorithm
(algorithm
) are also available. For the details of
arguments of dNMF, see ?dNMF
. After the calculation,
various objects are returned by dNMF
.
## List of 6
## $ U : num [1:100, 1:5] 0.979 0.979 0.979 0.979 0.979 ...
## $ V : num [1:300, 1:5] 0.999 0.999 0.999 0.999 0.999 ...
## $ RecError : Named num [1:101] 1.00e-09 1.34e+01 1.34e+01 1.34e+01 1.34e+01 ...
## ..- attr(*, "names")= chr [1:101] "offset" "1" "2" "3" ...
## $ TrainRecError: Named num [1:101] 1.00e-09 1.34e+01 1.34e+01 1.34e+01 1.34e+01 ...
## ..- attr(*, "names")= chr [1:101] "offset" "1" "2" "3" ...
## $ TestRecError : Named num [1:101] 1e-09 0e+00 0e+00 0e+00 0e+00 0e+00 0e+00 0e+00 0e+00 0e+00 ...
## ..- attr(*, "names")= chr [1:101] "offset" "1" "2" "3" ...
## $ RelChange : Named num [1:101] 1.00e-09 1.19e-04 1.43e-04 1.49e-04 1.48e-04 ...
## ..- attr(*, "names")= chr [1:101] "offset" "1" "2" "3" ...
The reconstruction error (RecError
) and relative error
(RelChange
, the amount of change from the reconstruction
error in the previous step) can be used to diagnose whether the
calculation is converged or not.
layout(t(1:2))
plot(log10(out_BMF$RecError[-1]), type="b", main="Reconstruction Error")
plot(log10(out_BMF$RelChange[-1]), type="b", main="Relative Change")
The product of \(U\) and \(V\) shows whether the original data is
well-recovered by dNMF
.
recX <- out_BMF$U %*% t(out_BMF$V)
layout(t(1:2))
image.plot(X, main="Original Data", legend.mar=8)
image.plot(recX, main="Reconstructed Data (BMF)", legend.mar=8)
The histograms of \(U\) and \(V\) show that both \(U\) and \(V\) take values close to 0 and 1.
Note that these \(U\) and \(V\) do not always take the values of 0 and 1 completely. This is because the binarization in BMF is based on the regularization to softly set the values as close to {0,1} as possible, and is not a hard binarization.
## [,1] [,2] [,3] [,4] [,5]
## [1,] 0.979044 0 0 3.765852e-104 0
## [2,] 0.979044 0 0 4.277338e-106 0
## [3,] 0.979044 0 0 2.301292e-104 0
## [4,] 0.979044 0 0 1.337948e-104 0
## [5,] 0.979044 0 0 9.347010e-105 0
## [6,] 0.979044 0 0 8.698401e-105 0
## [,1] [,2] [,3] [,4] [,5]
## [1,] 0.9988044 1.072698e-56 0 0.0013906118 0.000000e+00
## [2,] 0.9988248 5.888980e-54 0 0.0003300704 1.735858e-209
## [3,] 0.9988038 4.861490e-57 0 0.0014216661 0.000000e+00
## [4,] 0.9988042 5.637380e-58 0 0.0014015649 0.000000e+00
## [5,] 0.9988029 1.288196e-54 0 0.0014663748 0.000000e+00
## [6,] 0.9988025 6.724228e-58 0 0.0014901051 0.000000e+00
If you want to get the {0,1} values, use the round
function as below:
## [,1] [,2] [,3] [,4] [,5]
## [1,] 1 0 0 0 0
## [2,] 1 0 0 0 0
## [3,] 1 0 0 0 0
## [4,] 1 0 0 0 0
## [5,] 1 0 0 0 0
## [6,] 1 0 0 0 0
## [,1] [,2] [,3] [,4] [,5]
## [1,] 1 0 0 0 0
## [2,] 1 0 0 0 0
## [3,] 1 0 0 0 0
## [4,] 1 0 0 0 0
## [5,] 1 0 0 0 0
## [6,] 1 0 0 0 0
Next, we consider the approximation of a non-negative data matrix \(X\) (\(N \times M\)) as the matrix product of binary matrix \(U\) (\(N \times J\)) and non-negative matrix \(V\) (\(M \times J\)):
\[ X \approx U V' \ \mathrm{s.t.}\ U \in \{0,1\}, V \geq 0 \]
Here, we define this formalization as semi-binary matrix factorization (SBMF). SBMF can capture discrete patterns from a non-negative matrix.
To demonstrate SBMF, next we use a non-negative matrix from the
nnTensor
package.
You will see that there are five blocks in the data matrix as follows.
Switching from BMF to SBMF is quite easy; SBMF is achieved by specifying the binary regularization parameter as a large value like below:
## List of 6
## $ U : num [1:100, 1:5] 0.978 0.984 0.985 0.988 0.977 ...
## $ V : num [1:300, 1:5] 98.5 100.7 100 101.5 100.6 ...
## $ RecError : Named num [1:101] 1.00e-09 2.99e+03 2.92e+03 2.83e+03 2.77e+03 ...
## ..- attr(*, "names")= chr [1:101] "offset" "1" "2" "3" ...
## $ TrainRecError: Named num [1:101] 1.00e-09 2.99e+03 2.92e+03 2.83e+03 2.77e+03 ...
## ..- attr(*, "names")= chr [1:101] "offset" "1" "2" "3" ...
## $ TestRecError : Named num [1:101] 1e-09 0e+00 0e+00 0e+00 0e+00 0e+00 0e+00 0e+00 0e+00 0e+00 ...
## ..- attr(*, "names")= chr [1:101] "offset" "1" "2" "3" ...
## $ RelChange : Named num [1:101] 1.00e-09 2.60e-01 2.44e-02 3.18e-02 2.27e-02 ...
## ..- attr(*, "names")= chr [1:101] "offset" "1" "2" "3" ...
RecError
and RelChange
can be used to
diagnose whether the calculation is converged or not.
layout(t(1:2))
plot(log10(out_SBMF$RecError[-1]), type="b", main="Reconstruction Error")
plot(log10(out_SBMF$RelChange[-1]), type="b", main="Relative Change")
The product of \(U\) and \(V\) shows whether the original data is
well-recovered by dNMF
.
recX2 <- out_SBMF$U %*% t(out_SBMF$V)
layout(t(1:2))
image.plot(X2, main="Original Data", legend.mar=8)
image.plot(recX2, main="Reconstructed Data (SBMF)", legend.mar=8)
The histograms of \(U\) and \(V\) show that \(U\) looks binary but \(V\) does not.
Finally, we expand the binary regularization to ternary regularization to take {0,1,2} values as below:
\[ X \approx U V' \ \mathrm{s.t.}\ U \in \{0,1,2\}, V \geq 0, \] where \(X\) (\(N \times M\)) is a non-negative data matrix, \(U\) (\(N \times J\)) is a ternary matrix, and \(V\) (\(M \times J\)) is a non-negative matrix.
STMF is achieved by specifying the ternary regularization parameter as a large value like the below:
## List of 6
## $ U : num [1:100, 1:5] 2.02 2.02 2.02 2.02 2.02 ...
## $ V : num [1:300, 1:5] 48.7 49.8 49.5 50.2 49.8 ...
## $ RecError : Named num [1:101] 1.00e-09 2.52e+03 2.58e+03 2.59e+03 2.58e+03 ...
## ..- attr(*, "names")= chr [1:101] "offset" "1" "2" "3" ...
## $ TrainRecError: Named num [1:101] 1.00e-09 2.52e+03 2.58e+03 2.59e+03 2.58e+03 ...
## ..- attr(*, "names")= chr [1:101] "offset" "1" "2" "3" ...
## $ TestRecError : Named num [1:101] 1e-09 0e+00 0e+00 0e+00 0e+00 0e+00 0e+00 0e+00 0e+00 0e+00 ...
## ..- attr(*, "names")= chr [1:101] "offset" "1" "2" "3" ...
## $ RelChange : Named num [1:101] 1.00e-09 1.22e-01 2.12e-02 3.09e-03 2.03e-03 ...
## ..- attr(*, "names")= chr [1:101] "offset" "1" "2" "3" ...
RecError
and RelChange
can be used to
diagnose whether the calculation is converging or not.
layout(t(1:2))
plot(log10(out_STMF$RecError[-1]), type="b", main="Reconstruction Error")
plot(log10(out_STMF$RelChange[-1]), type="b", main="Relative Change")
The product of \(U\) and \(V\) shows that the original data is
well-recovered by dNMF
.
recX <- out_STMF$U %*% t(out_STMF$V)
layout(t(1:2))
image.plot(X2, main="Original Data", legend.mar=8)
image.plot(recX, main="Reconstructed Data (STMF)", legend.mar=8)
The histograms of \(U\) and \(V\) show that \(U\) looks ternary but \(V\) does not.
## R version 4.3.1 (2023-06-16)
## Platform: x86_64-pc-linux-gnu (64-bit)
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## attached base packages:
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## [1] nnTensor_1.2.0 fields_15.2 viridisLite_0.4.2 spam_2.9-1
## [5] dcTensor_1.3.0
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